Question

1 Evaluate int (tan x +sec x) sec^2 dx​

Answer 1

Step-by-step explanation:

(tanx + secx ) sec^2x dx

tanx sec^2x + secx.sec^2x

tanx sec^2x dx + secx sec^2x dx

= tanx sec^2x + secx (tan^2x+1)dx

first integrat

=tanx sec^2x

substiute tanx =u

derivatives du/dx=sec^2x

sec^2x=du

=u du

=u^2/2

put value tan^2x/2

secx= secx+tanx