Question

1.
EXERCISE 5.1
Obtain the equation of the circles with radius 5 cm and touching x-axis at the origin in
Find the equation of the circle with centre (2,-1) and passing through the point
form.​

Answer 1

Answer:

please say the answer

Step-by-step explanation:

Answer 2

Given a circle of radius r=5

Given center lies on x-axis. 

So, let the center be (h,0)

Equation of circle is

(x−h)2+y2=25       ....(1)

Since, it passes through (2,3)

⇒(2−h)2+32=25

⇒(2−h)2=16

⇒2−h=±4

⇒h=−2,h=6

When h=−2, the equation of circle is 

(x+2)2+y2=25

⇒x2+4x+4+y2=25

⇒x2+y2+4x−21=0

When h=6, the equation of circle is 

(x−6)2+y2=25

⇒x2−12x+36+y2=25

⇒x2+y2−12x+11=0