1. Explain the action of dilute HCL
the following with chemical
equatás
1) magnesium ribbon
2) sadium
Hydroxide
3)crushed egg shell
Answers
Answer:
Reactions of hydrochloric acid with magnesium ribbon ,sodium hydroxide and crushed egg shell.
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✴Reaction of hydrochloric acid with magnesium ribbon.
In this reaction hydrochloric acid react with magnesium ribbon and form magnesium chloride and hydrogen gas.
2HCl+ Mg =========》 MgCl2 +H2
✴Reaction of hydrochloric acid with sodium hydroxide.
HCl+ NaOH ========》NaCl + H2O
that is when hydrochloric acid react with Sodium Hydroxide it leads to the formation of the salt sodium chloride and water.
✴Reaction with crushed egg cell.
2HCl+ CaCO3 ========》CaCl2 + CO2 + H2O
when hydrochloric acid reacts with crushed egg shells and utilise to you formation of calcium chloride carbon dioxide gas and water.
Answer:
hydroxide acid is the answer