Question

1. Express 63 as the sum of consecutive odd numbers.​

Answer 1

Step-by-step explanation

31+33+35+37+39+41

We know,

1=1=1^{3} ,

3+5=8=2^{3} ,

7+9+11=27=3^{3 },

13+15+17+19=64=4^{3} ,

21+23+25+27+29=125=5^{3} ,

31+33+35+37+39+41=216=6^{3} .

Therefore, the sum of odd consecutive cube number for 6^{3} =216

must be 31+33+35+37+39+41.

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