1/f = 1/50 _ 1/(_50) is =to how much
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0+50 = 50
1+49 = 50
2+48 = 50
…etc…
24+26 = 50
25
So for the first 25 sums (0 to 24 is 25 sums), the answer is 50, therefore the total for the first 25 sums is 25x50. Now add the last one, 25.
25 + 25x50 = 1275
I did not look anything up to find this. I just thought about ways to add all the numbers in such a way that I could see a pattern so I was not required to brute-force add all the numbers.
Then knowing that 5x any number is half the number times 10, 25/2 = 12.5 times 10 is 125. Then since it is 50, not 5, times 10 again for 1250. Add 25 and get 1275. Much simpler and I can do it all in my head.
Ironically, when you type in 25x50 on a calculator, it is adding 50 to itself 25 times. But it is much faster.
1+49 = 50
2+48 = 50
…etc…
24+26 = 50
25
So for the first 25 sums (0 to 24 is 25 sums), the answer is 50, therefore the total for the first 25 sums is 25x50. Now add the last one, 25.
25 + 25x50 = 1275
I did not look anything up to find this. I just thought about ways to add all the numbers in such a way that I could see a pattern so I was not required to brute-force add all the numbers.
Then knowing that 5x any number is half the number times 10, 25/2 = 12.5 times 10 is 125. Then since it is 50, not 5, times 10 again for 1250. Add 25 and get 1275. Much simpler and I can do it all in my head.
Ironically, when you type in 25x50 on a calculator, it is adding 50 to itself 25 times. But it is much faster.
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