Question

(1). Factorise:
a) (1 + m) - (I- m)?
b) 4x2 + 12x + 9


(2). The length of a diagonal of a quadrilateral and the length of the two perpendiculars drawn from the remaining two vertices are 121 m, 40 m
and 80 m respectively. Find the area of the quadrilateral.

(Plz friends give the answer and explanation of these two questions and Don't spam otherwise reported...)​

Answer 1

Answer:

The area of the quadrilateral is 7260 cm².

step by step explanation

The diagonal of a quadrilateral, d = 121 m

The length of the perpendiculars drawn to the diagonal from the opposite vertices are h₁ = 40 m and h₂ = 80 m

The formula of the area of a quadrilateral is given by,

Area = ½ * [diagonal] * [sum of the lengths of the perpendiculars drawn from the opposite vertices to the diagonal]

Now, substituting the given values in the above formula of the area we get,

Area of the quadrilateral = ½ * d * [h₁ + h₂]  

⇒ Area of the quadrilateral = ½ * 121 * [40 + 80]

⇒ Area of the quadrilateral = ½ * 121 * 120

⇒ Area of the quadrilateral = 60 * 121

⇒ Area of the quadrilateral = 7260 cm²