Question

1. Factorize:
(a) 8x cube + 27 y cube​

Answer 1

Step-by-step explanation:

Hey There,

Here we are going to use the identity :

a^3+b^3 = (a+b)(a^2-ab+b^2)a

3

+b

3

=(a+b)(a

2

−ab+b

2

)

We can solve this question in the same way as follows:

\begin{gathered}8x^3+27y^3 \\ \\ =(2x)^3+(3y)^3 \\ \\ =(2x+3y)((2x)^2-(2x)(3y)+(3y)^2) \\ \\ = (2x+3y)(4x^2-6xy+9y^2)\end{gathered}

8x

3

+27y

3

=(2x)

3

+(3y)

3

=(2x+3y)((2x)

2

−(2x)(3y)+(3y)

2

)

=(2x+3y)(4x

2

−6xy+9y

2

)

Hope it helps....

by Jessica Jennah Angel

Answer 2

Answer:

$8 {x}^{3} + 27 {y}^{3} \\ = (2 {x})^{3} + (3 {y})^{3} \\ = (2x + 3y) {}^{3} - 3.2x.3y(2x + 3y) \\ = (2x + 3y) {}^{3} - 18xy(2x + 3y)$