Question

1. Factorize the following: 81p^2q^4-p^2q^6.​

Answer 1

$\huge\underline\mathbb\blue{ANSWER}$

$\: \: \: \: \: \: \: \: 81 {p}^{2} 2 {q}^{4} - {p}^{2} 2 {q}^{6} \\ \\ = > {p}^{2} 2 {q}^{6} (81 - 1) \\ \\ = > {p}^{2} 2 {q}^{6} (80) \\ \\ = > 80{p}^{2} 2 {q}^{6}$

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