1. Factorize: x³-2x²-5x-6, 6-2+x² , (5a+2/3)² - (2a-1/3)²
2. If (a, b) = (0, -2) Find the value of a and b.
3. Verify if 1 and -3 are zeroes of the polynomial 3x³+5x²-11x+3. If yes, then factorize the polynomial.
4. If f(x) = x³-3x²+3x-4, find f(2)+f(-2)+f(0)
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4. f(2)=2^3-3(2)^2+3(2)-4
=8-12+6-4
=14-16
f(2) = -2
f(-2)=(-2)^3-3(-2)^2+3(-2)-4
= -8-12-6-4
=-30
f(0)=0-0+0-4
f(0)= -4
so f(2)+f(-2)+f(0)= -2-30-4
=-36
=8-12+6-4
=14-16
f(2) = -2
f(-2)=(-2)^3-3(-2)^2+3(-2)-4
= -8-12-6-4
=-30
f(0)=0-0+0-4
f(0)= -4
so f(2)+f(-2)+f(0)= -2-30-4
=-36
aleenasara:
incomplete?
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