Question

1). find (3-2x) (3+2x)
2). write 4 solution of x=4y
3). find the value of K, if X=2, Y=1is a solution of the equation 2x+3y=k.
4). A die is thrown. find the probability of getting an odd number.



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Answer 1

I can give yu only 1 , 3 , 4 i don't know 2 sorry...

Answer 2

$Question:1$

$(3-2x)(3+2x)\\\\= 3^2-(2x)^2[a^2-b^2 =(a+b)(a-b)]\\\\= 9-4x^2$

$Question:2$

Write 4 solution of x = 4y.

For x = -4

$-4=4y\\\\y = -1$

• So (-4,-1) is a solution of this equation.

For x = 2

$2=4y\\\\y = \frac{1}{2}$

• So (2,1/2)is a solution of this equation.

You may find so on in this way.

$Question:3$

$x=2\\\\y=1\\\\So\\\\2x+3y=k\\\\=>k=2*2+3*1\\So\\k=4+3=7.$

$Question:4$

A dice is thrown.Find the probability of getting an odd no.

$P[E]=\frac{Favourable outcomes}{Totaloutcomes} \\\\=\frac{3}{6} = \frac{1}{2} .$

Thanks..