(1) Find a pair of integers whose product is - 15 and whose difference is
(ii) Find a pair of integers whose product is – 36 and whose difference is 15
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If it helps mark me as brainliestand in first part I have taken 8 as a difference
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Step-by-step explanation:
(i) There are few pairs of integers whose product is – 15. e.g. – 1 × 15 – 3 × 5 3 × – 5 15 × – 1 but difference of –3 and 5 or –5 and 3 is 8. So the required pair of integers is – 3 5 and – 5 3.
(ii) The pair of integers are x=3 and y=-12 or x=12 and y=-3 whose product is -36 and their difference will be 15.
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Answer:
A pair of integers whose product −36
and difference =15
These integers can be −12 and 3
as −12×3=−36
and 3−(−12)=3+12=15
Other pair can be −3,12 as
−3+12=−36
and 12−(−3)
=12+3=15
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