Question

1) Find HCE
( i) 21658 and 8624
21658=8624 xa +4410
8624 4410 X 17 4214
시 410 4alu X1 + 196
4214 196 X 21+ 98
196
98 X 2 to
since i=0;
i since
98 is the HLF​

Answer 1

Answer:

Euclid division lemma:-

a = bq + r

0 ≤ r < b

a > b

(i)8624 and 21658

21658 = 8624(2) + 4410

8624 =4410(1) + 4214

4410 = 4214(1) + 196

4214 = 196(21) + 98

196 = 98(2) + 0

HCF of 8624 and 21658 is 98,

(ii)4052 and 12576

12576 = 4052(3) + 420

4052 = 420(9) + 272

420 = 272(1) + 148

272 = 148(1) + 124

148 = 124(1) + 24

124 = 24(5) + 4

24 = 4(6) + 0

HCF of 4052 and 12576 is 4.

Hope it helps...

Explanation:

please please mark me as brainliest

plz plz plz