Question

1) find hypotenuse if base = 6cm and perpendicular =8cm 2) In what rate of interest will the interest on Rs 4500 in 6 years be Rs 1350 ?​

Answer 1

for q-1)10cm

Step-by-step explanation:

(hypotenuse)sqr=(base)sqar+(perpendicular)sqr

(hypotenuse)sqr= 36+64=100

so hypotenuse=10 cm

Answer 2

$\large\bf\underline {To \: find:-}$

• we need to find Hypotenuse in 1st Question.

• In Second Question we need to find The rate of interest.

$\huge\bf\underline{Solution:-}$

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1)find hypotenuse if base = 6cm and perpendicular =8cm.

⇝ Given :-

• Base = 6cm
• perpendicular = 8cm

➣ By using Pythagoras theorem

➣ Hypotenuse ² = base² + perpendicular ²

↛ Hypotenuse ² = 6² + 8²

↛ Hypotenuse ² = 36 + 64

↛ Hypotenuse = √100

↛ Hypotenuse = 10cm

Hence ,

• Hypotenuse = 10cm

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2) In what rate of interest will the interest on Rs 4500 in 6 years be Rs 1350 ?

⇝ Given :-

• Principal = Rs 4500
• Time = 6 years
• Intrest = 1350

we know that,

$\bigstar\star \red{ \bf \: Simple \: Interest = \frac{ P \times R \times T}{100}}$

↛ 1350 = 4500× R × 6 × 100

↛ 1350×100 = 27000R

↛ 135000/27000 = R

↛ 135/27 = R

↛ R = 5

Hence,

• At 5% rate of interest will the interest on Rs 4500 in 6 years be Rs 1350.

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