Question

1) Find it's velocity, 2) Find it's acceleration, 3) Distance covered by cycle in 15 sec.​

Answer 1

Answer:

velocity=20

acceleration=0

distance=300

Answer 2

Answer- The above question is from the chapter 'Kinematics'.

Some important terms and formulae:-

1. Velocity- It is the displacement per unit time.

S.I. Unit of Velocity- m/s

It is a vector quantity as it possesses magnitude and direction.

2. Acceleration- It is the rate of change of velocity.

S.I. Unit of Acceleration- m/s²

It is also a vector quantity.

Negative acceleration is called retardation.

3. Distance- It is the path length transversed by an object.

S.I. Unit of Distance- m

It is a scalar quantity.

4. Displacement- It is the shortest distance between the initial and final point.

S.I. Unit of Displacement- m

It is a vector quantity.

5. Equations for uniformly accelerated motion-

Let u = Initial velocity of a particle

v = Final velocity of a particle

t = Time taken

s = Distance travelled in the given time

a = Acceleration

1) v = u + at

2) s = $\frac{1}{2}$ at² + ut

3) v² - u² = 2as

6. Average Speed = Total distance ÷ Total time

7. Average Velocity = Total displacement ÷ Total time

8. Some basic formulae using calculus method:

1) Velocity = $\frac{dx}{dt}$

2) Acceleration = $\frac{dv}{dt}$

3) Acceleration (when x is given) = $v \frac{dv}{dx}$

Concept used: 1) In a velocity-time graph,

slope of the graph = acceleration

area of the graph = distance/displacement covered

2) If velocity is constant, there is no acceleration as slope = 0.

Given question: Find

1) velocity

2) acceleration

3) distance covered by cycle in 15 sec.

(Velocity-Time Graph has been attached in the question.)

Answer: 1) Velocity is constant.

Clearly, velocity = 20 m/s.

2) Slope of the graph = 0.

So, acceleration = 0 m/s².

3) Distance covered by cycle in 15 sec = Area under the graph

                                                                   = 20 × 15

                                                                   = 300 m

So, distance covered by cycle in 15 sec = 300 m.