Question

1. Find LCM &HCF : a)12,56,72 , b)36,108,212 .
2. If the HCF of 692 and 436 is 4 , find LCM(692,436).

Answer 1

Heya!

Here is ur answer...

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(1) HCF of

(a) 12, 56 ,72

12 = 2² × 3¹

56 = 2³ × 7

72 = 2³ × 3²

Therefore,

HCF = 2² × 3¹ = 12

(b) 36,108, 212

36 = 2² × 3²

108 = 2² × 3³

212 = 2² × 53

Therefore,

HCF = 2² × 3² = 36

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(2)

Given, HCF of 692 and 436 = 4

As we know,

HCF × LCM = product of two no.s

4 × LCM = 692 × 436

LCM = 692×436/4

LCM = 75428

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Hope it helps!

Answer 2

HCF OF

●12,56,72

$12 = {2}^{2} \times 3 \\ \\ 56 = {2}^{3} \times 7 \\ \\ 72 = {2}^{3} \times {3}^{2} \\ \\ \\ hcf = {2}^{2} \times {3}^{1} = 12$

HCF OF

●36,108,212

$36 = {2}^{2} \times {3}^{2} \\ \\ 108 = {2}^{2} \times {3}^{3} \\ \\ 212 = {2}^{2} \times 53$

$hcf \: {2}^{2} \times {3}^{2} = 36$

2) given HCF of (692,436) =4

we know

HCF×LCM= PRODUCT of TWO NO.

4×LCM=692×436

$lcm = \frac{ 692 \times 436 }{4} \\ \\ = > 75428$