1. Find out the value of B if 1B x B=96
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B=6... its a small value so you can guess
Since there is only one variable you can do this too
B(10+B)=96
Thus B^2 + 10B -96 = 0
=> B^2 + 16B - 6B - 96 = 0
=> (B+16)(B-6)0
So B=6
If there is more then 1 variable then u have to do hit and trial, seeing unit digit etc
Since there is only one variable you can do this too
B(10+B)=96
Thus B^2 + 10B -96 = 0
=> B^2 + 16B - 6B - 96 = 0
=> (B+16)(B-6)0
So B=6
If there is more then 1 variable then u have to do hit and trial, seeing unit digit etc
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