Question

1. Find the 10th term of the A.P whose sum of n terms is given by 2n2 + 3n.
(a) 4
(6) 14
(c) 40
(d) 41​

Answer 1

Answer:

1st term=2(1)2+3(1)=4+3=7

2nd term =2(2)2+3(2)=8+6=14

t2-t1=14-7=7=d

10 th term = 7+9(7)=7+63=70

Answer 2

so the tenth term of the AP 5,9,13..... is 41