Question

1.Find the acceleration and displacement of a body whose velocity time graph is show in the picture.

Answer 1

HEY BUDDY...!!!

HERE IS UR ANSWER..

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▶️ Acceleration , there are three cases

#1. From point A to B object has accelerated

=> Acceleration from A to B

=> Time = 2 s

=> u ( initial velocity ) = 0

=> v ( final velocity ) = 10 m / s

=> Acceleration = ( v - u ) / t

=> Acceleration = 10 - 0 / 2

=. Acceleration = 5 m / s^2

#2. Acceleration from B to C is 0

=> It is parallel to x - axis
, it means object is moving with constant velocity , hence Acceleration = 0

#3. Acceleration from C to D

=> Time = 2 s

=> u ( initial velocity ) = 10 m / s

=> v ( final velocity ) = 0 m / s

=> Acceleration = ( v - u ) / t

=> Acceleration = 0 - 10 / 2

=. Acceleration = -5 m / s^2

Hence object is retarding

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▶️ We know displacement is given by area under v - t graph

Displacement is area of 2 right triangles of dimensions , height ( h ) = 10 m and base ( b ) = 2 m , area rectangle of dimensions length ( l ) = 6 m and breadth ( B ) = 10 m

So,

=> Displacement = 2 ( 1 / 2 b . h ) + l × B

=> Displacement = b . h + B . h

=> Displacement = 10 . 2 + 10 . 6

=> Displacement = 20 + 60

=> Displacement = 80 m

HOPE HELPED..

HAVE A NICE DAY..

:-)

Answer 2

displacement is 80 m
acceleration is 0.8m/s²