1. Find the area of a rectangular plot one side of which is 48 m and its diagonal 50 m...
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Answered by
2
Diagonal = 50 m
Base = 48 m
x square = √50 square - 48 square
x = 14 m
Area of rectangle = l × b
= (48 × 14) m sq...
= 672 m sq...
Hope this helped.....
Answered by
4
Answer:
Let ABCD be the rectangular plot. Then, AB = 48 m and AC = 50 m BC =?
According to Pythagoras theorem, From right angle triangle ABC, we have:
= AC2 = AB2 + BC2
= 502 = 482 + BC2
= BC2 = 502 – 482
= BC2 = 2500 – 2304
= BC2 = 196
=BC = √196
= BC = 14 m
Hence, the area of the rectangle plot
= (l × b)
Where, l = 48 m, b = 14 m
Then, = (48 × 14)
= 672 m2
Step-by-step explanation:
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