Question

1. Find the area of a sector of a circle with radius 6 cm if angle of the sector is 60°​

Answer 1

Step-by-step explanation:

Radius of a sector of a circle, r = 6 cm.

Angle of a sector of a circle, θ = 60°

Area of a sector of a circle = ?

Area of a sector of a circle

= \(\frac{\theta}{360}\times \pi r ^2\)

= 18.8 sq.cm.

Answer 2

Step-by-step explanation:

$\mathfrak{ \huge{ \green{ \underline{given}}}} \\ \mathfrak{ \large{ \red{radius \: = \: 6 \: cm}}} \\ \mathfrak{ \large{ \red{angle \: of \: sector \: (θ) = {60}^{o}}}} \\ \mathfrak{ \huge{ \green{ \underline{to \: find}}}} \\ \mathfrak{ \large{ \red{area \: of \: sector \: = \: ?}}} \\ \mathfrak{ \huge{ \green{ \underline{formula \: to \: be \: used}}}} \\ \mathfrak{ \large{ \red{area \: of \: sector \: = \: \frac{θ}{360} \: \times \: \pi {r}^{2} }}} \\ \mathfrak{ \huge{ \green{ \underline{solution}}}} \\ \mathfrak{ \large{ \blue{area \: of \: sector \: = \frac{θ}{360} \times \pi {r}^{2}}}} \\ \mathfrak{ \large{ \blue{area \: of \: sector \: = \: \frac{60}{360} \times \frac{22}{7} \times 6 \times 6 }}} \\ \mathfrak{ \large{ \blue{area \: of \: sector \: = \: \frac{1}{6} \times \frac{22}{7} \times 6 \times 6 }}} \\ \mathfrak{ \large{ \blue{area \: of \: sector \: = \: \frac{22}{7} \times 6}}} \\ \mathfrak{ \large{ \orange{ \underline{area \: of \: sector \: = \: \frac{132}{7} {cm}^{2} }}}}$