1.find the area of circle whose circumference is 44cm?
2.log(a+b)+log(a-b)-log(a2-b2)
3.The perimeter of a square circumscribing a circle of radius a units is
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radius of circle = R cm
2 π R = circumference = 44
2 * 22 / 7 * R = 44 cm
R = 7 cm
Area = π R² = 22/7 * 7² = 154 cm²
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Log x + Log y = Log x * y
Log x - Log y = Log x/y
Log (a+b) + Log (a-b) - Log (a² - b²)
= Log (a+b)(a-b)/(a²-b²) = Log 1 = 0
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square circumscribes a circle of radius a units.
The line segment joining centers of opposite sides is the diameter of the circle.
So side of square = diameter of circle = 2 a
perimeter = 4 * 2 a = 8 a units
2 π R = circumference = 44
2 * 22 / 7 * R = 44 cm
R = 7 cm
Area = π R² = 22/7 * 7² = 154 cm²
==============
Log x + Log y = Log x * y
Log x - Log y = Log x/y
Log (a+b) + Log (a-b) - Log (a² - b²)
= Log (a+b)(a-b)/(a²-b²) = Log 1 = 0
====================
square circumscribes a circle of radius a units.
The line segment joining centers of opposite sides is the diameter of the circle.
So side of square = diameter of circle = 2 a
perimeter = 4 * 2 a = 8 a units
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