Question

1. Find the centroid of A ABC whose vertices are A (1,-1), B (0,6) and C (-3,0)​

Answer 1

to find this use this fomula fomula x1+x2+x3 /3),(y1+y2+y3/3)

Answer 2

$\huge{\mathcal{\blue{\underline{Answer}}}}$

✔ Given that the coordinates of the vertices of triangle ABC ➡ A(1,-1) , B(0,6) and C(-3,0)

☑ Centroid of the triangle :

$= ( \frac{x _{1} + x _{2} + x _{3} }{3} ).( \frac{y _{1} + y _{2} + y _{3} }{3} ) \\ = ( \frac{1 + 0 + ( - 3)}{3} ).( \frac{ - 1 + 6 + 0}{3} ) \\ = (\frac{1 - 3}{3} ).( \frac{ - 1 + 6}{3} ) \\ = ( \frac{ - 2}{3} ).( \frac{5}{3} )$

☑ The Coordinates are :

$\huge{\mathcal{\blue{\underline{(-2/3,5/3)}}}}$