Question

1. Find the cost of watering a trapezoidal field whose parallel sides are 10 m and 25 m respectively
perpendicular distance between them is 15 m and, the rate of watering is . 4 per​

Answer 1

Given the parallel sides as 10 m & 25 m.

=1000 cm & 2500 cm

And the distance between them = 15 cm

So the area of the trapezium = ½ × 15 ×(1000+2500) cm²

= ½ × 15 ×3500 cm²

= 15 × 1750 cm²

= 26250 cm²

=2.625 m²

₹4 costs per 1 square metre watering.

So 2.625 square metre will cost = ₹2.625 × 4

= ₹ 10.5

That's it

Hope it helped

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