Question

1. Find the cube of the following
i.
3x + 4
formulas of cube
(a+b)³ =a³+3ab(a+b)+b³
the one who ans me right ill give brainlest ​

Answer 1

Answer

$27 {x}^{3} + 108 {x}^{2} + 144x + 64$

Steps

${(3x + 4)}^{3} \\ = {(3x)}^{3} + 3 \times 3x \times 4(3x + 4) + {4}^{3} \\ = 27 {x}^{3} + 36x(3x + 4) + 64 \\ = 27 {x}^{3} + 108 {x}^{2} + 144x + 64$

Answer 2

Answer

27 {x}^{3} + 108 {x}^{2} + 144x + 6427x

3

+108x

2

+144x+64

Steps

=(3x) 3 +3×3x×4(3x+4)+4

=27x

3

+36x(3x+4)+64

=27x

3

+108x

2

+144x+64