Question

1. find the equation of parabola whose foucs (6, 0) and directrix x= 6

Answer 1

(x−h)2=4p(y−k)(x−h)2=4p(y−k)

(h,k)=(3,0)(h,k)=(3,0)

(x−3)2=12y(x−3)2=12y as p = 3

However, the answer shows that it's y2=12x−36