Question

1. Find the equations of tangent and normal to the
curve y = x⁴- 6x³ + 13x² -10x + 5 at (0,5).​

Answer 1

Answer:

At (0,5) slope of tangent is -10

Step-by-step explanation:

Equation of tangent is y-5=-10x

Slope of normal at (0,5) is 1/10

Equation of normal is 10y-50=x

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