1) Find the HCF of 140,160,240 by using:-
a) Prime factorization
b) Short division method
c) Long division method
2) Find the LCM of 102,170,136 by using the prime factorization method and short division method.
3) Find the greatest four-digit number and the smallest four-digit number that is divisible by 16 and 80
4) A merchant has 120 liters of oil of one kind, 180 liters of another king, and 240 liters of the third kind. He wants to sell the oil by filling the three kinds of oil in tins of equal capacity. What should be the greatest capacity of such a tin?
Answers
Step-by-step explanation:
4) We need to find the HCF or GCD that is Greatest Common Divisor
We need to find the HCF or GCD that is Greatest Common Divisor 120=2
We need to find the HCF or GCD that is Greatest Common Divisor 120=2 3
We need to find the HCF or GCD that is Greatest Common Divisor 120=2 3 ×3×5
We need to find the HCF or GCD that is Greatest Common Divisor 120=2 3 ×3×5180=2
We need to find the HCF or GCD that is Greatest Common Divisor 120=2 3 ×3×5180=2 2
We need to find the HCF or GCD that is Greatest Common Divisor 120=2 3 ×3×5180=2 2 ×3
We need to find the HCF or GCD that is Greatest Common Divisor 120=2 3 ×3×5180=2 2 ×3 2
We need to find the HCF or GCD that is Greatest Common Divisor 120=2 3 ×3×5180=2 2 ×3 2 ×5
We need to find the HCF or GCD that is Greatest Common Divisor 120=2 3 ×3×5180=2 2 ×3 2 ×5240=2
We need to find the HCF or GCD that is Greatest Common Divisor 120=2 3 ×3×5180=2 2 ×3 2 ×5240=2 4
We need to find the HCF or GCD that is Greatest Common Divisor 120=2 3 ×3×5180=2 2 ×3 2 ×5240=2 4 ×3×5
We need to find the HCF or GCD that is Greatest Common Divisor 120=2 3 ×3×5180=2 2 ×3 2 ×5240=2 4 ×3×5GCD=2
We need to find the HCF or GCD that is Greatest Common Divisor 120=2 3 ×3×5180=2 2 ×3 2 ×5240=2 4 ×3×5GCD=2 2
We need to find the HCF or GCD that is Greatest Common Divisor 120=2 3 ×3×5180=2 2 ×3 2 ×5240=2 4 ×3×5GCD=2 2 ×3×5=60
We need to find the HCF or GCD that is Greatest Common Divisor 120=2 3 ×3×5180=2 2 ×3 2 ×5240=2 4 ×3×5GCD=2 2 ×3×5=60The greatest capacity = 60 liters
We need to find the HCF or GCD that is Greatest Common Divisor 120=2 3 ×3×5180=2 2 ×3 2 ×5240=2 4 ×3×5GCD=2 2 ×3×5=60The greatest capacity = 60 litersSo the merchant needs to fill 60 liters of all types of oils
2) in photo