1. Find the HCF of the following by factorization: (a) 140 and 196 (b) 352 and 192 (d) 540,315 and 360 (e) 216,324 and I 350
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Answer:
28 , 32 , 45 , 54
Step-by-step explanation:
Factors of 140: 1, 2, 4, 5, 7, 10, 14, 20, 28, 35, 70, 140
Factors of 196: 1, 2, 4, 7, 14, 28, 49, 98, 196
Therefore, the HCF of 140 and 196 is 28.
352 = 2 × 2 × 2 × 2 × 2 × 11 192 = 2 × 2 × 2 × 2 × 2 × 2 × 3
Therefore, HCF = 2 × 2 × 2 × 2 × 2 = 32
540 = 2x2x3x3x3x5 315 = 3x3x5x7 360 = 2x2x2x3x3x5
Therefore, the HCF = 3x3x5 = 45
216=2*2*2*3*3*3 324=2*2*3*3*3*3 1350=2*3*3*3*5*5
Therefore, the HCF =2*3*3*3 = 54
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