Question

1. Find the least number which is a perfect square and which is also divisible by
12,15 and 21.​

Answer 1

Answer:

44100

Step-by-step explanation:

LCM (12,15,21) = 420 = 4 × 3 × 5 × 7

So, the required no should be multiple of 420.

Hence, required no = 2^2 × 3^2 × 5^2 × 7^2 = 44100

Hope, it helps you.

Answer 2

Find the least number which is a perfect square and which is also divisible by

12,15 and 20

____________________________________________________________________

SOL: 12 = 2×2×3

15= 3×5

20 = 2×2×5

So LCM wil be

2×2×3×5 =60

As 3 and 5 are not in pair in LCM's

factor , so we need to multiply 60 by 3

and 5.

60×3×5 = 900.

So the number is 900.