Question

(1) Find the least number which when
divided by 8, 12 and 20 leaves
remainder 5 in each case.​

Answer 1

Answer:

840 is the LCM of the given numbers. For a remainder of 5 in each case, 5 has to be added to this number. Hence 840 + 5 =845 will be the required number..please mark as brainliest

Answer 2

Step-by-step explanation:

the LCM of 8,12 and 20 is 840

We want that number if we add 5 in 840

= 845 if we divide it by given numbers our remainder is 5

So our required number is 845