Question

1. Find the
molarity of a solution
prepared by dissolving 45g glucose in 1000ml water.​

Answer 1

Answer:

The molarity of the solution is 0.5 moles per liter of solution.

Answer 2

Given:-

→ Mass of glucose = 45g

→ Volume of solution = 1000mL

To find:-

→ Molarity of the solution.

Solution:-

• Molar mass of Carbon = 12g/mol

• Molar mass of Hydrogen = 1g/mol

• Molar mass of Oxygen = 16g/mol

Hence, molar mass of glucose [C6H12O6] :-

= 12×6 + 1×12 + 16×6

= 72 + 12 + 96

= 180g/mol

Number of mole in 45g of glucose :-

= Given Mass/Molar mass

= 45/180

= 0.25 mole

Now, let's convert the volume of the solution from mL to L.

=> 1mL = 0.001L

=> 1000mL = 1000(0.001)

=> 1L

Molarity of a solution :-

= Moles of solute/Liters of solution

= 0.25/1

= 0.25 M

Thus, molarity of the solution

is 0.25 M .