Question

1. Find the perimeter of rhombus, the lengths of whose diagonals are 16 cm and 30 cm .15cm .

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Answer 1

Answer:

Step-by-step explanation:

given,the measures of diagonals16,30

We know that diagonals of rhombus are perpendicular bisectors of each other.

db=16

DO=DB/2

DO=16/2

DO=8cm

similarly, AO=15cm

by using pythogoras theorem,

DO²+AO²=DA²

8²+15²=DA²

64+225=DA²

289=DA²

DA=17

perimeter=DA×4

             =17×4

perimeter=68CM

i hope this helps

Answer 2

Answer:

$\huge{\underline{\underline{\mathbb{\blue{Answer}}}}}$

$✬p \: = 68cm$

$p \: diagonal \: = 16cm$

$q \: diagonal \: = 30cm$

$➟a \: = \frac{ \sqrt{ {p}^{2} + {q}^{2} } }{2}$

Solving for P

$➫ \: p = \sqrt{ {p}^{2} {q}^{2} } = 2 . \sqrt{ {16}^{2} + {3}^{2} } = 68cm$

★★Hope it's help you.... ★★