Question

1. Find the perimeter of rhombus, the lengths of whose diagonals are 16 cm and 30 cm.
15cm
Bem
to the​

Answer 1

suppose it as a rhombus of 4 trianges joint as a rhombus use the Pythagoras ppty. and here u go

suppose it as a rhombus of 4 trianges joint as a rhombus use the Pythagoras ppty. and here u goHOPE U GOT IT

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Answer 2

Answer:

68 cm

Explanation:

Length of diagonals of rhombus = 16 cm and 30 cm

=> perimeter of rhombus = 2√(d1)^2 +(d2)^2

=>length of d1 = 16 cm and d2 = 30 cm

=> p= 2√16^2 + 30^3

=> p = 2√ 256 + 900

=> p = 2(34)

=> p = 68 cm