Question

1. Find the probability that a non-leap year selected at random will contain 53 Sundays.
2
(A)
(B)
(C)
(D) 1
7
7
(c)​

Answer 1

Answer:

4

Step-by-step explanation:

Answer 2

Answer : 1/7 ✔✔

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Solution :

A non-leap year has 365 days.

365 days = 52 weeks + 1 day

1 week has 7 days

To find :

Probability of being 53 sundays in a non-leap year

Number of favourable events = E = Sunday

=> n(E) = 1

And Number of total events = S = Sunday, Monday, Tuesday, Wednesday, Thursday, Friday and Saturday

=> n(S) = 7

As we know that :

Probability = Number of favourable events/Number of total events

=> P = n(E)/n(S) = 1/7

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Hope it helps ☺

Fóllòw Më ❤