Question

1. Find the product of the following binomials.
1. (5× +3) (2× +4)​

Answer 1

Answer:

$(5x + 3)(2x + 4) \\ = > 10 {x}^{2} + 20x + 6x + 12 \\ = > 10 {x}^{2} + 26x + 12 \\ take \: 2 \: as \: a \: common\\ = > 5 {x}^{2} + 13x + 6 \\ = > 5 {x}^{2} + 10x + 3x + 6 \\ = > 5x(x + 2) + 3(x + 2) \\ = > (5x + 3)(x + 2) \\ = > 5x + 3 = 0 \\ = > 5x = - 3 \\ = > x = \frac{ - 3}{5} \\ \\ = > x + 2 = 0 \\ = > x = - 2$

Answer 2

AnswEr-:

• $\underline{\boxed{\mathrm{\dag{\blue{ Answer -: 5x^{2} + 13x +6}}}}}$

Explanation-:

• $\mathrm { Find \:the\:product\:of\:the\:bionomial-:}$

• $\longrightarrow{\mathrm{ ( 5x + 3) ( 2x +4)}}$

$\mathrm{\dag{Solution \:of\:Question-:}}$

• $\longrightarrow{\mathrm{ ( 5x + 3) ( 2x +4)}}$

• $\mathrm { Now,\:multiplyin\:one\:bionomial\:to\:other\:bionomial-:}$

• $\longrightarrow{\mathrm{ ( 5x + 3) ( 2x +4)}}$

• $\longrightarrow{\mathrm{ 5x ( 2x +4)+ 3(2x +4)}}$

• $\longrightarrow{\mathrm{ 10x^{2} + 20x + 3(2x +4)}}$

• $\longrightarrow{\mathrm{ 10x^{2} + 20x + 6x +12}}$

$\mathrm { Now,\:By\:Adding\:like\:terms-:}$

• $\longrightarrow{\mathrm{ 10x^{2} + 20x + 6x +12}}$

• $\longrightarrow{\mathrm{ 10x^{2} + 20x + 6x +12}}$

• $\longrightarrow{\mathrm{ 10x^{2}+ 26x +12}}$

$\mathrm { Now,\:Taking\:2\:as\:Common\:in\:each\:term\:-:}$

$\mathrm {Or,}$

$\mathrm { Now,\:Devide\:each\:term\:devide\:by\:2\:\:-:}$

• $\longrightarrow{\mathrm{ 10x^{2}+ 26x +12}}$

• $\longrightarrow{\mathrm{ \cancel{10x^{2}}+ \cancel{26x} +\cancel{12}}}$

• $\longrightarrow{\mathrm{ 5x^{2}+ 13x +6}}$

$\mathrm{\dag{Hence-:}}$

• $\underline{\boxed{\mathrm{\dag{\blue{ Answer -: 5x^{2} + 13x +6}}}}}$

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