Question

1. Find the range of the values of k if kx2 +8x > 6-k for all real values of x.
where k is positive​

Answer 1

I'm unsure if the discriminant must be greater than zero or less than zero.

My working steps:

b2−4ac=(8)2−4(−2)(17−k)64−4(−2)(17−k)64+136−8k200>0>0>0>8k

so my answer is

k<200/8.

Answer 2

Answer:

Your answer is k <200/8