the distance of point p (3,a ), and q(9,4) is 10 then find value of a
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2
Answer:
Distance between two point (x1,y1) and (x2,y2) is given by,
=(x2−x1)2+(y2−y1)2
102=(y+3)2+(10−2)2
(y+3)2=102−82
(y+3)2=62
y+3=±6
∴y=3ory=−9
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Answer:
the distance of point p (3,a ), and q(9,4) is 10
then find value of a
Step-by-step explanation:
then the value of a is 1 ,2
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