Question

1. Find the remainder when x + 3.x2 + 3x + 1 is divided by 5+ 2x

pls ans ​

Answer 1

Answer:

Remainder = (39/4)

Step-by-step explanation:

Let p(x) = x+3x²+3x+1 = 3x²+(x+3x)+1 = 3x²+4x+1

     g(x) = (2x+5)

Zero of g(x) => (2x+5) = 0             =>2x = (-5)             =>x = (-5/2)

p(-5/2) = 3(-5/2)²+ 4(-5/2)+1 = 3(25/4)+2(-5)+1 = 75/4-10+1 = 75/4-9

= (75-36)/4 = 39/4

Hence, The required remainder is (39/4)

Answer 2

Answer:

The remainder is = 57/2

Step-by-step explanation:

f(x) = x+3x^2+3x+1

g(x) = 5+2x

       2x = -5

        x = -5/2

So, f(-5/2) = (-5/2) + 3(-5/2)^2 + 3(-5/2) + 1

      =  -5/2 + 75/2 - 15/2 + 1

      =   -5 + 75 - 15/2 + 1

      =   75 - 20/2 + 1

      =     55/2 + 1

      =    55 + 2/2

      =     57/2

hence the remainder is = 57/2

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