Question

1. Find the sides of rhombus whose
diagonals
are 16 cm and 12 cm.​

Answer 1

$p = 16 \: cm \\ q = 12 \: cm \\ a = \frac{ \sqrt{ {p}^{2} + {q}^{2} } }{2} \\ \\ = \frac{ \sqrt{ {16}^{2} + {12}^{2} } }{2 } \\ \\ = 10 \: cm$