Question

1. Find the simple interest and the amount at simple interest of

(a) Rs.350 for 3 years at 6%​

Answer 1

Step-by-step explanation:

Given:

Principal (P)=Rs.350

Time(T)= 3 years

Rate of interest= 6p.c.p.a

To find:

Simple Interest

Amount

Formula:

Simple Interest= P×T×R/100

Amount= S. I.+ Principal

Proof(Solution):

Simple Interest= P×T×R/100

= 350×3×6/100

= 35×3×6/100 ......

( cancelling 0 at both sides)

= 630/10

=63

thus,

Simple Interest= Rs.63

Amount= S.I + Principal

= 63 + 350

= 413

thus,

Amount=Rs. 413

Answer 2

Answer:

• Given the required data to find the simple interest and the amount at simple interest ✓

The data are as follows:

$= > \red{ \: principal(p) = RS \: 350} \ \\ \\ = > \red{\ time \: = 3years} \\ \\ = > \red{\ rate \: of \: interest = 6\%}$

So by using this data we need to calculate out the Simple interest and the Amount at simple interest of that principal ✓

So let us determine the values :

$for \: calculating \: those \: values \: we \: need \: to \: apply \: the following \: \: formula \: \\ \boxed{ \red{simple \: interest(si) = \frac{p \times r \times t}{100} }}$

And

$\red{ \boxed{amount = simple \: interest(si) \: + principal(p)}}$

So firstly we need to calculate out the Simple interest (SI) which is as follows

$\bold{ = > si = \frac{p \times r \times t}{100}} \\ \\ = > \bold{ si = \frac{350 \times 3 \times 6}{100}} \\ \\ = > \bold{si = \frac{6300}{100}} \\ \\ = > \bold{ \red{si = 63}}$

So from the above calculation we find the simple interest is 63✓

Now ,The amount is as follows

$= > \bold{amount \: = si + p} \\ \\ = > \bold{amount = 63 + 350} \\ \\ = > \bold{ \red{amount = 413}}$