Question

1. Find the smallest number which when added to 9 is exactly divisible by 12, 15, 20 and 27.
2. What is the least number that must be subtracted from 3000 so that the difference is divisible exactly by 32, 36 and 48 ?
3. Find the least 4-digit number which when divided by 24, 16 and 12 leaves a remainder 5 in each case.



Please answer!!
It's urgent​

Answer 1

1.27+9=36
2. the divide the number and you will get some remainder that is the answer......
15÷4 u will get 3 as a remainder ,three is the Sub from 15 u get 12 ...12 is exactly divisible by 4