Question

A particle position as a function of time is described as y(t)=2t^2+3t^2+4. what is the avarage velocity of the particle t=0to t=3sec
Answer should be 9m/s

Answer 1

Answer:

9m/s

Explanation:

Hey mate I think that your given expression is wrong

the correct expression is 2t²+3t+4

now we will differentiate y(t)

so it will be as follows

4t+3

now we need v and u

so u=4(0)+3=3m/s for t=0

and v=4(3)+3=15m/s. for t=3

now average velocity is v+u/2

i.e 3+15/2

=18/2

=9m/s

Thank you

d__sahil

Regards