Math, asked by jaswanthgosangi, 9 months ago

1.Find the smallest number, which when divided by 30 and 45 leaves as remainder in
both the cases.

Answers

Answered by joshiseth333

1

Answer:

find the HCF of 30 and 45

which is 15

it can be found it by equilds division algorithm

45=30×1+15

30=15×2+0

here,it can be clearly seen that 15 is the hcf

Answered by sanket2984

0

Answer:

rftgh no iik

Step-by-step explanation:

very fv3ec to uhihcrdryfkivguygcufcytviuuvvbhbhbnfcv ctfuhguhu

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