Question

1.Find the son of the hall
a. 21, 28, 36, 45
b.22,54,108, 135 and 198.
c.48.64, 72, 96, 108
2. Find the HCF of the following (prime factorisation method)
a.144, 180,192
b. 136, 170, 255
c. 72,108, 180​

Answer 1

Answer:

Step-by-step explanation:

Find the HCF of the following (prime factorisation method)

a.144, 180,192

b. 136, 170, 255

c. 72,108, 180​

a.144, 180,192

144 = 2 * 2 * 2 * 2 * 3 * 3

180 = 2 * 2 * 3 * 3 * 5

192 = 2 * 2 * 2 * 2 * 2 * 2 * 3

2 * 2 * 3 = 12 is HCF

b. 136, 170, 255

136 = 2 * 2 * 2 * 17

170 = 2 * 5 * 17

255 = 3 * 5 * 17

HCF = 17

c. 72,108, 180​

72 = 2 * 2 * 2 * 3 * 3

108 = 2 * 2 * 3 * 3 * 3

180 = 2 * 2 * 3 * 3 * 5

2 * 2 * 3 * 3  = 36 is HCF