Question

1) Find the square root of the expression
x²/y2-10x/y+27-10y/x+y2/x2​

Answer 1

By taking L.C.M, we get

(x4 - 10x3y + 27x2y2 - 10xy3+ y4)/x2y2

=  √(x4 - 10x3y + 27x2y2 - 10xy3+ y4)/√x2y2



  =  (x2 - 5xy + y2)/xy

  =  (x/y)  - 5 + (y/x)

Hence the square root of the polynomial (x2/y2) - 10x/y + 27 - (10y/x) + (y2/x2) is (x/y)  - 5 + (y/x).

Let us look into the next example on "Finding the Square Root of a Polynomial by Long Division Method".

Answer 2

Answer:

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