Physics, asked by tanvi881, 10 months ago

(1) Find the steady current flowing through a metal
wire when 3 1018 electrons pass across a cross-
section of the wire in one minute.

Answers

Answered by acv49

1

Answer:

8.01 mA

Explanation:

6.2415*10^18 electron per sec =1 Amp

So 3*10^18 per min

=(3/60)*10^18/sec

=(1/20)*10^18/sec

but 6.2415*10^18/sec=1 Amp

so 1/20....=8.01miliAmp

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