Math, asked by kavithathirumal52098, 8 months ago

1. Find the value of 5V6 + 3V6
3. Is the number (5 + V4)(5 – V4) rational or Irrational ?
4.Ifa = 6 + 2V3, find the value of
а-1/a​

Answers

Answered by gautamkumar118
0

Step-by-step explanation:

1) \: 5 \sqrt{6}  + 3 \sqrt{6}  \\  \:  \:  \:  = (5 + 3) \sqrt{6}  \\  \:  \:  \:  = 8 \sqrt{6}  \\  \\ 2) \: (5 +  \sqrt{4} )(5 -  \sqrt{4} ) \\  by \: using \: identiy \: (x + y)(x - y) =  {x}^{2}  -  {y}^{2}  \\ then \: x = 5 \: and \: y \:  =  \sqrt{4}  \\ so \: put \: the \: value \: of \: x \: and \: y \\ (5 +  \sqrt{4} )(5 -  \sqrt{4} ) \\  =  {5}^{2}  -  { \sqrt{4} }^{2}  \\  = 25 - 4 \\  = 21 \\ It \: is \: written \: in \: the\: form \: of \:  \frac{p}{q}(q≠0).\\So, \: it \: is \: a \: rational \: number \:

=6 + 2 \sqrt{3}  -  \frac{1}{6 + 2 \sqrt{3}}  \\  =  \frac{(6 + 2 \sqrt{3})(6 + 2 \sqrt{3}) - 1}{6 + 2 \sqrt{3}}  \\  =  \frac{36 + 24 \sqrt{3}  + 12 - 1}{6 + 2 \sqrt{3}}   \\  =  \frac{47  + 24 \sqrt{3}}{6 + 2 \sqrt{3}}

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