Question

1) Find the value of ‘a’ if x=1 and y=3 is a solution of ax + 4y=14.

2) Write the equations of a line equidistant from the x-axis and the y-axis at any point on the line.

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Answer 1

Answer:

Q1.) Putting x=1 and y=3 in equation ax+4y=14.

a×1+4×3=14

a+12=14

a=14-12

a=2

So, value of a is 2.

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Answer 2

Answer:

1) a = 2

2) x=y and x= -y

Step-by-step explanation:

1) if x is 1 and y is 3 then,

a+12=14

a=2.ans