Question

1) Find the value of k, such that (x-1) is the factor of x²+9x-5+k.

Answer 1

Answer:

k=-5

Step-by-step explanation:

Given----->

if (x-1) is factor of x²+9x-5+k

to find value of K

{x}^{2} + 9x - 5 + k = 0 \\ \\

{1}^{2} + 9 \times 1 - 5 + k = 0 \\ \\

1 + 9 - 5 + k = 0 \\ \\

5 + k = 0 \\ \\

k = - 5\

x2+9x−5+k=0

12+9×1−5+k=0

1+9−5+k=0

5+k=0

k=−5

Answer 2

Answer:

x²+9x-5+k

Put x=1 (factor theorem)

1+9-5+k=0

5+k=0 k=-5

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