Question

1.
Find the values of the following
1)6!
2)8!
3)7!/3!
4)9!-6!/4!
5)(2n)!/n!

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Answer 1

Answer:

1) 6! = 6×5×4×3×2×1 = 720

2) 8! = 8×7×6×5×4×3×2×1 = 40,320

3) 7!/31 = 7×6×5×4×3!/3! = 840

4) 9! - 6!/4! = 3!/4×3! = 1/4

5) (2n)!/ n! = 2n!(n-1)!/n! = 2n-1

Answer 2

Step-by-step explanation:

1)6! =1 X 2 X 3 X 4 X 5 X 6

= 720

2)8! = 1 X 2 X 3 X 4 X 5 X 6 X 7 X 8

= 40320

3)7!/3!

= 1 X 2 X 3 X 4 X 5 X 6 X 7 /1 X 2 X 3

= 840

4)9! - 6!/4!

= 1 X 2 X 3 X 4 X 5 X 6 X 7 X 8 X 9 - = 1 X 2 X 3 X 4 X 5 X 6 /= 1 X 2 X 3 X 4

=362880- 30

= 362850

5)(2n)!/n

2n X (2n-1) X....(n+1) X n X (n -1) X..... X 1/n X (n -1) X..... X 1

= 2n X (2n-1) X....(n+1)